What are the solutions to the equation 6x^2-150x+1531=159x-5x^2+1531 ?

The solutions to the equation 6x^2-150x+1531=159x-5x^2+1531 are x= 309/11 ,x=0

Find the zeros of 6x^2-150x+1531=159x-5x^2+1531

The zeros of 6x^2-150x+1531=159x-5x^2+1531 are x= 309/11 ,x=0

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6 x^{2} - 150 x + 1531 = 159 x - 5 x^{2} + 1531

x = \frac{309}{11}, x = 0

Decimal Notation

x = 28.09090 \dots, x = 0

Solution steps

6 x^{2} - 150 x + 1531 = 159 x - 5 x^{2} + 1531

Move

1531

to the left side

6 x^{2} - 150 x = 159 x - 5 x^{2}

Move

5 x^{2}

to the left side

11 x^{2} - 150 x = 159 x

Move

159 x

to the left side

11 x^{2} - 309 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 309 ) \pm ( - 309 ) ^{2} - 4 \cdot 11 \cdot 0}{2 \cdot 11}

(- 309)^{2} - 4 \cdot 11 \cdot 0 = 309

x_{1, 2} = \frac{- ( - 309 ) \pm 309}{2 \cdot 11}

Separate the solutions

x_{1} = \frac{- ( - 309 ) + 309}{2 \cdot 11}, x_{2} = \frac{- ( - 309 ) - 309}{2 \cdot 11}

x = \frac{- ( - 309 ) + 309}{2 \cdot 11} : \frac{309}{11}

x = \frac{- ( - 309 ) - 309}{2 \cdot 11} : 0

The solutions to the quadratic equation are:

x = \frac{309}{11}, x = 0

6 x^{2} - 6 x = 36

g^{2} = 375

x^{2} - 2 x - 168 = 0

x, (x + y + 1) (x + y - 1) = 1

100 x^{2} = 81

What are the solutions to the equation 6x^2-150x+1531=159x-5x^2+1531 ?
The solutions to the equation 6x^2-150x+1531=159x-5x^2+1531 are x= 309/11 ,x=0
Find the zeros of 6x^2-150x+1531=159x-5x^2+1531
The zeros of 6x^2-150x+1531=159x-5x^2+1531 are x= 309/11 ,x=0