What are the solutions to the equation -4x^2+10x-4=0 ?

The solutions to the equation -4x^2+10x-4=0 are x= 1/2 ,x=2

Find the zeros of -4x^2+10x-4=0

The zeros of -4x^2+10x-4=0 are x= 1/2 ,x=2

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- 4 x^{2} + 10 x - 4 = 0

x = \frac{1}{2}, x = 2

Decimal Notation

x = 0.5, x = 2

Solution steps

- 4 x^{2} + 10 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 4 ) ( - 4 )}{2 ( - 4 )}

1 0^{2} - 4 (- 4) (- 4) = 6

x_{1, 2} = \frac{- 10 \pm 6}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 10 + 6}{2 ( - 4 )}, x_{2} = \frac{- 10 - 6}{2 ( - 4 )}

x = \frac{- 10 + 6}{2 ( - 4 )} : \frac{1}{2}

x = \frac{- 10 - 6}{2 ( - 4 )} : 2

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = 2

x, x^{2} - 18 x y + y^{2} = 18

6 x^{2} + 6 x + 16 = 5 x^{2} + 2

0 = 6 x^{2} + 18

x, 13 x^{2} - 10 x y + 13 y^{2} = 72

s^{2} - 2 s - 1 = 0

What are the solutions to the equation -4x^2+10x-4=0 ?
The solutions to the equation -4x^2+10x-4=0 are x= 1/2 ,x=2
Find the zeros of -4x^2+10x-4=0
The zeros of -4x^2+10x-4=0 are x= 1/2 ,x=2