What are the solutions to the equation -5x^2+19x+176=-7x^2-x ?

The solutions to the equation -5x^2+19x+176=-7x^2-x are x=-5+3sqrt(7)i,x=-5-3sqrt(7)i

Find the zeros of -5x^2+19x+176=-7x^2-x

The zeros of -5x^2+19x+176=-7x^2-x are x=-5+3sqrt(7)i,x=-5-3sqrt(7)i

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- 5 x^{2} + 19 x + 176 = - 7 x^{2} - x

x = - 5 + 37 i, x = - 5 - 37 i

Solution steps

- 5 x^{2} + 19 x + 176 = - 7 x^{2} - x

Move

x

to the left side

- 5 x^{2} + 20 x + 176 = - 7 x^{2}

Move

7 x^{2}

to the left side

2 x^{2} + 20 x + 176 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 2 \cdot 176}{2 \cdot 2}

Simplify

2 0^{2} - 4 \cdot 2 \cdot 176 : 127 i

x_{1, 2} = \frac{- 20 \pm 12 7 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 20 + 12 7 i}{2 \cdot 2}, x_{2} = \frac{- 20 - 12 7 i}{2 \cdot 2}

x = \frac{- 20 + 12 7 i}{2 \cdot 2} : - 5 + 37 i

x = \frac{- 20 - 12 7 i}{2 \cdot 2} : - 5 - 37 i

The solutions to the quadratic equation are:

x = - 5 + 37 i, x = - 5 - 37 i

x, - x^{2} + \frac{7}{2} x = \frac{1}{2} x^{2} - 4 x + 6

p^{2} - 12 p + 88 = 0

2 x^{2} + 3 x = 8

x^{2} + 4 - 5 x = 0

1 5^{2} + y^{2} = 1 7^{2}

What are the solutions to the equation -5x^2+19x+176=-7x^2-x ?
The solutions to the equation -5x^2+19x+176=-7x^2-x are x=-5+3sqrt(7)i,x=-5-3sqrt(7)i
Find the zeros of -5x^2+19x+176=-7x^2-x
The zeros of -5x^2+19x+176=-7x^2-x are x=-5+3sqrt(7)i,x=-5-3sqrt(7)i