What are the solutions to the equation solvefor x,z=x^2+y ?

The solutions to the equation solvefor x,z=x^2+y are x=sqrt(z-y),x=-sqrt(z-y)

Find the zeros of solvefor x,z=x^2+y

The zeros of solvefor x,z=x^2+y are x=sqrt(z-y),x=-sqrt(z-y)

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solve for

x, z = x^{2} + y

x = z - y, x = - z - y

Solution steps

z = x^{2} + y

Switch sides

x^{2} + y = z

Move

y

to the right side

x^{2} = z - y

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = z - y, x = - z - y

l, T = 2 π l^{2}

x, 4 x^{2} + 4 y^{2} - 12 x + 27 = 0

25 = x^{2} + x + 4

x^{2} + 3 x - 5 = 0

a^{2} + 7^{2} = 1 4^{2}

What are the solutions to the equation solvefor x,z=x^2+y ?
The solutions to the equation solvefor x,z=x^2+y are x=sqrt(z-y),x=-sqrt(z-y)
Find the zeros of solvefor x,z=x^2+y
The zeros of solvefor x,z=x^2+y are x=sqrt(z-y),x=-sqrt(z-y)