What are the solutions to the equation x^{1+log_{x}(16)}=4x^2 ?

The solutions to the equation x^{1+log_{x}(16)}=4x^2 are x=0,x=4

Find the zeros of x^{1+log_{x}(16)}=4x^2

The zeros of x^{1+log_{x}(16)}=4x^2 are x=0,x=4

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x^{1 + l o g_{x} (16)} = 4 x^{2}

x = 0, x = 4

Solution steps

x^{1 + l o g_{x} (16)} = 4 x^{2}

Move

4 x^{2}

to the left side

16 x - 4 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 4 x^{2} + 16 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 4 ) \cdot 0}{2 ( - 4 )}

1 6^{2} - 4 (- 4) \cdot 0 = 16

x_{1, 2} = \frac{- 16 \pm 16}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 16 + 16}{2 ( - 4 )}, x_{2} = \frac{- 16 - 16}{2 ( - 4 )}

x = \frac{- 16 + 16}{2 ( - 4 )} : 0

x = \frac{- 16 - 16}{2 ( - 4 )} : 4

The solutions to the quadratic equation are:

x = 0, x = 4

71 x^{2} - 810 x + 1944 = 0

0.03 q^{2} - 1.2 q + 17 = 0

2 = (x + 2)^{2}

- 5 x^{2} - 3 x - 1 = 0

(x - 8)^{2} = - 49

What are the solutions to the equation x^{1+log_{x}(16)}=4x^2 ?
The solutions to the equation x^{1+log_{x}(16)}=4x^2 are x=0,x=4
Find the zeros of x^{1+log_{x}(16)}=4x^2
The zeros of x^{1+log_{x}(16)}=4x^2 are x=0,x=4