What are the solutions to the equation 0=-x^2+6x-7 ?

The solutions to the equation 0=-x^2+6x-7 are x=3-sqrt(2),x=3+sqrt(2)

Find the zeros of 0=-x^2+6x-7

The zeros of 0=-x^2+6x-7 are x=3-sqrt(2),x=3+sqrt(2)

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0 = - x^{2} + 6 x - 7

x = 3 - 2, x = 3 + 2

Decimal Notation

x = 1.58578 \dots, x = 4.41421 \dots

Solution steps

0 = - x^{2} + 6 x - 7

Switch sides

- x^{2} + 6 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 1 ) ( - 7 )}{2 ( - 1 )}

6^{2} - 4 (- 1) (- 7) = 22

x_{1, 2} = \frac{- 6 \pm 2 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 2}{2 ( - 1 )}, x_{2} = \frac{- 6 - 2 2}{2 ( - 1 )}

x = \frac{- 6 + 2 2}{2 ( - 1 )} : 3 - 2

x = \frac{- 6 - 2 2}{2 ( - 1 )} : 3 + 2

The solutions to the quadratic equation are:

x = 3 - 2, x = 3 + 2

40 - x^{2} = 0

x^{2} - 33 = 0

\frac{x ^{2}}{4} = x - 2

2 x^{2} + 6 x - 10 = 0

2 y^{2} + 7 y + 6 = 0

What are the solutions to the equation 0=-x^2+6x-7 ?
The solutions to the equation 0=-x^2+6x-7 are x=3-sqrt(2),x=3+sqrt(2)
Find the zeros of 0=-x^2+6x-7
The zeros of 0=-x^2+6x-7 are x=3-sqrt(2),x=3+sqrt(2)