What are the solutions to the equation 2m^2-7m+5=0 ?

The solutions to the equation 2m^2-7m+5=0 are m= 5/2 ,m=1

Find the zeros of 2m^2-7m+5=0

The zeros of 2m^2-7m+5=0 are m= 5/2 ,m=1

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2 m^{2} - 7 m + 5 = 0

m = \frac{5}{2}, m = 1

Decimal Notation

m = 2.5, m = 1

Solution steps

2 m^{2} - 7 m + 5 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 \cdot 5}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 \cdot 5 = 3

m_{1, 2} = \frac{- ( - 7 ) \pm 3}{2 \cdot 2}

Separate the solutions

m_{1} = \frac{- ( - 7 ) + 3}{2 \cdot 2}, m_{2} = \frac{- ( - 7 ) - 3}{2 \cdot 2}

m = \frac{- ( - 7 ) + 3}{2 \cdot 2} : \frac{5}{2}

m = \frac{- ( - 7 ) - 3}{2 \cdot 2} : 1

The solutions to the quadratic equation are:

m = \frac{5}{2}, m = 1

25 (y + 5)^{2} = 81

7 x^{2} + 27 x - 4 = 0

x^{2} + 5 x + 4 = 9

x^{2} + \frac{4}{9} x

x (2 x + 1) = 3

What are the solutions to the equation 2m^2-7m+5=0 ?
The solutions to the equation 2m^2-7m+5=0 are m= 5/2 ,m=1
Find the zeros of 2m^2-7m+5=0
The zeros of 2m^2-7m+5=0 are m= 5/2 ,m=1