What are the solutions to the equation x^2+5x=-6 ?

The solutions to the equation x^2+5x=-6 are x=-2,x=-3

Find the zeros of x^2+5x=-6

The zeros of x^2+5x=-6 are x=-2,x=-3

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x^{2} + 5 x = - 6

x = - 2, x = - 3

Solution steps

x^{2} + 5 x = - 6

Move

6

to the left side

x^{2} + 5 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 6 = 1

x_{1, 2} = \frac{- 5 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 1}{2 \cdot 1}, x_{2} = \frac{- 5 - 1}{2 \cdot 1}

x = \frac{- 5 + 1}{2 \cdot 1} : - 2

x = \frac{- 5 - 1}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = - 2, x = - 3

16 x = 30

lo g_{3} (9 x)

\frac{18 !}{11 ! ( 7 ! )}

(\frac{5}{2})^{4} + 1

\frac{3}{2} x - 4 = 16

What are the solutions to the equation x^2+5x=-6 ?
The solutions to the equation x^2+5x=-6 are x=-2,x=-3
Find the zeros of x^2+5x=-6
The zeros of x^2+5x=-6 are x=-2,x=-3