What are the solutions to the equation (x^2-10x+25)+6=42 ?

The solutions to the equation (x^2-10x+25)+6=42 are x=11,x=-1

Find the zeros of (x^2-10x+25)+6=42

The zeros of (x^2-10x+25)+6=42 are x=11,x=-1

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(x^{2} - 10 x + 25) + 6 = 42

x = 11, x = - 1

Solution steps

(x^{2} - 10 x + 25) + 6 = 42

Refine

x^{2} - 10 x + 31 = 42

Move

42

to the left side

x^{2} - 10 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot ( - 11 )}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot (- 11) = 12

x_{1, 2} = \frac{- ( - 10 ) \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 12}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 12}{2 \cdot 1}

x = \frac{- ( - 10 ) + 12}{2 \cdot 1} : 11

x = \frac{- ( - 10 ) - 12}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 11, x = - 1

\frac{1}{2} x^{2} = - 32

3 = 11 m^{2}

2 x^{2} - 5 x + 25 = 0

x^{2} - 1 x = 0

(x - 2)^{3} - (x - 3)^{3} = 33

What are the solutions to the equation (x^2-10x+25)+6=42 ?
The solutions to the equation (x^2-10x+25)+6=42 are x=11,x=-1
Find the zeros of (x^2-10x+25)+6=42
The zeros of (x^2-10x+25)+6=42 are x=11,x=-1