What are the solutions to the equation j^2-5j+6=0 ?

The solutions to the equation j^2-5j+6=0 are j=3,j=2

Find the zeros of j^2-5j+6=0

The zeros of j^2-5j+6=0 are j=3,j=2

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j^{2} - 5 j + 6 = 0

j = 3, j = 2

Solution steps

j^{2} - 5 j + 6 = 0

Solve with the quadratic formula

j_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 6 = 1

j_{1, 2} = \frac{- ( - 5 ) \pm 1}{2 \cdot 1}

Separate the solutions

j_{1} = \frac{- ( - 5 ) + 1}{2 \cdot 1}, j_{2} = \frac{- ( - 5 ) - 1}{2 \cdot 1}

j = \frac{- ( - 5 ) + 1}{2 \cdot 1} : 3

j = \frac{- ( - 5 ) - 1}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

j = 3, j = 2

x^{2} + 10 x + 16

x, x^{2} - 2 x - 4 y + 5 = 0

x^{2} + 10 x + 23

(x - 12)^{2} = 54

y^{2} = - 3

What are the solutions to the equation j^2-5j+6=0 ?
The solutions to the equation j^2-5j+6=0 are j=3,j=2
Find the zeros of j^2-5j+6=0
The zeros of j^2-5j+6=0 are j=3,j=2