What are the solutions to the equation 7x^2+4x+2=0 ?

The solutions to the equation 7x^2+4x+2=0 are x=-2/7+i(sqrt(10))/7 ,x=-2/7-i(sqrt(10))/7

Find the zeros of 7x^2+4x+2=0

The zeros of 7x^2+4x+2=0 are x=-2/7+i(sqrt(10))/7 ,x=-2/7-i(sqrt(10))/7

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7 x^{2} + 4 x + 2 = 0

x = - \frac{2}{7} + i \frac{10}{7}, x = - \frac{2}{7} - i \frac{10}{7}

Solution steps

7 x^{2} + 4 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 7 \cdot 2}{2 \cdot 7}

Simplify

4^{2} - 4 \cdot 7 \cdot 2 : 210 i

x_{1, 2} = \frac{- 4 \pm 2 10 i}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 4 + 2 10 i}{2 \cdot 7}, x_{2} = \frac{- 4 - 2 10 i}{2 \cdot 7}

x = \frac{- 4 + 2 10 i}{2 \cdot 7} : - \frac{2}{7} + i \frac{10}{7}

x = \frac{- 4 - 2 10 i}{2 \cdot 7} : - \frac{2}{7} - i \frac{10}{7}

The solutions to the quadratic equation are:

x = - \frac{2}{7} + i \frac{10}{7}, x = - \frac{2}{7} - i \frac{10}{7}

6 r^{2} - 4 r - 80 = 0

12 x^{2} - 128 x + 252 = 0

y, 5 x^{2} + 2 x^{2} y + y^{2} = 8

x^{2} = 8 x + 10

t, t^{2} - 2 y t - 1 = 0

What are the solutions to the equation 7x^2+4x+2=0 ?
The solutions to the equation 7x^2+4x+2=0 are x=-2/7+i(sqrt(10))/7 ,x=-2/7-i(sqrt(10))/7
Find the zeros of 7x^2+4x+2=0
The zeros of 7x^2+4x+2=0 are x=-2/7+i(sqrt(10))/7 ,x=-2/7-i(sqrt(10))/7