What are the solutions to the equation x^2-2x+0.99=0 ?

The solutions to the equation x^2-2x+0.99=0 are x= 11/10 ,x= 9/10

Find the zeros of x^2-2x+0.99=0

The zeros of x^2-2x+0.99=0 are x= 11/10 ,x= 9/10

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x^{2} - 2 x + 0.99 = 0

x = \frac{11}{10}, x = \frac{9}{10}

Decimal Notation

x = 1.1, x = 0.9

Solution steps

x^{2} - 2 x + 0.99 = 0

Multiply both sides by

100

100 x^{2} - 200 x + 99 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 200 ) \pm ( - 200 ) ^{2} - 4 \cdot 100 \cdot 99}{2 \cdot 100}

(- 200)^{2} - 4 \cdot 100 \cdot 99 = 20

x_{1, 2} = \frac{- ( - 200 ) \pm 20}{2 \cdot 100}

Separate the solutions

x_{1} = \frac{- ( - 200 ) + 20}{2 \cdot 100}, x_{2} = \frac{- ( - 200 ) - 20}{2 \cdot 100}

x = \frac{- ( - 200 ) + 20}{2 \cdot 100} : \frac{11}{10}

x = \frac{- ( - 200 ) - 20}{2 \cdot 100} : \frac{9}{10}

The solutions to the quadratic equation are:

x = \frac{11}{10}, x = \frac{9}{10}

(3 x - 9) (x - 1) = 0

x^{2} + 10 x + 25 = 225

5 x^{2} + 38 - 3 = 0

3 u^{2} = 30 u - 6

5^{2} + 1 2^{2} = 2 x^{2}

What are the solutions to the equation x^2-2x+0.99=0 ?
The solutions to the equation x^2-2x+0.99=0 are x= 11/10 ,x= 9/10
Find the zeros of x^2-2x+0.99=0
The zeros of x^2-2x+0.99=0 are x= 11/10 ,x= 9/10