What are the solutions to the equation x=5x(1-x) ?

The solutions to the equation x=5x(1-x) are x=0,x= 4/5

Find the zeros of x=5x(1-x)

The zeros of x=5x(1-x) are x=0,x= 4/5

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x = 5 x (1 - x)

x = 0, x = \frac{4}{5}

Decimal Notation

x = 0, x = 0.8

Solution steps

x = 5 x (1 - x)

Expand

5 x (1 - x) : 5 x - 5 x^{2}

x = 5 x - 5 x^{2}

Switch sides

5 x - 5 x^{2} = x

Move

x

to the left side

- 5 x^{2} + 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 5 ) \cdot 0}{2 ( - 5 )}

4^{2} - 4 (- 5) \cdot 0 = 4

x_{1, 2} = \frac{- 4 \pm 4}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 4 + 4}{2 ( - 5 )}, x_{2} = \frac{- 4 - 4}{2 ( - 5 )}

x = \frac{- 4 + 4}{2 ( - 5 )} : 0

x = \frac{- 4 - 4}{2 ( - 5 )} : \frac{4}{5}

The solutions to the quadratic equation are:

x = 0, x = \frac{4}{5}

3 z^{2} - 4 z + 5 = 0

(x + 4) (x + 3) = 0

- x^{2} + x + \frac{11}{6} = 0

a, \int (x) d x = a^{2}

4 X^{2} = - 8

What are the solutions to the equation x=5x(1-x) ?
The solutions to the equation x=5x(1-x) are x=0,x= 4/5
Find the zeros of x=5x(1-x)
The zeros of x=5x(1-x) are x=0,x= 4/5