What are the solutions to the equation 4x^2-12x=-11 ?

The solutions to the equation 4x^2-12x=-11 are x= 3/2+i(sqrt(2))/2 ,x= 3/2-i(sqrt(2))/2

Find the zeros of 4x^2-12x=-11

The zeros of 4x^2-12x=-11 are x= 3/2+i(sqrt(2))/2 ,x= 3/2-i(sqrt(2))/2

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4 x^{2} - 12 x = - 11

x = \frac{3}{2} + i \frac{2}{2}, x = \frac{3}{2} - i \frac{2}{2}

Solution steps

4 x^{2} - 12 x = - 11

Move

11

to the left side

4 x^{2} - 12 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 11}{2 \cdot 4}

Simplify

(- 12)^{2} - 4 \cdot 4 \cdot 11 : 42 i

x_{1, 2} = \frac{- ( - 12 ) \pm 4 2 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4 2 i}{2 \cdot 4}, x_{2} = \frac{- ( - 12 ) - 4 2 i}{2 \cdot 4}

x = \frac{- ( - 12 ) + 4 2 i}{2 \cdot 4} : \frac{3}{2} + i \frac{2}{2}

x = \frac{- ( - 12 ) - 4 2 i}{2 \cdot 4} : \frac{3}{2} - i \frac{2}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2} + i \frac{2}{2}, x = \frac{3}{2} - i \frac{2}{2}

y^{2} = 33

y^{2} = 32

3 x^{2} + 4 x - 18 = 0

x^{2} + 18 x + 68 = 0

81 x^{2} - 72 x + 16 = 0

What are the solutions to the equation 4x^2-12x=-11 ?
The solutions to the equation 4x^2-12x=-11 are x= 3/2+i(sqrt(2))/2 ,x= 3/2-i(sqrt(2))/2
Find the zeros of 4x^2-12x=-11
The zeros of 4x^2-12x=-11 are x= 3/2+i(sqrt(2))/2 ,x= 3/2-i(sqrt(2))/2