What are the solutions to the equation p^2-5=4 ?

The solutions to the equation p^2-5=4 are p=3,p=-3

Find the zeros of p^2-5=4

The zeros of p^2-5=4 are p=3,p=-3

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p^{2} - 5 = 4

p = 3, p = - 3

Solution steps

p^{2} - 5 = 4

Move

5

to the right side

p^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

p = 9, p = - 9

9 = 3

- 9 = - 3

p = 3, p = - 3

x^{2} + 10 x + 12 = 0

12 (- 2 k - 4)^{2} - 1 (- 2 k - 4) - 6 = 0

y, x^{2} - x y + y^{2} = 3

5 x^{2} + 41 x - 36 = 0

x^{2} = 1.21

What are the solutions to the equation p^2-5=4 ?
The solutions to the equation p^2-5=4 are p=3,p=-3
Find the zeros of p^2-5=4
The zeros of p^2-5=4 are p=3,p=-3