What are the solutions to the equation x^2-23/12 x+10/12 =0 ?

The solutions to the equation x^2-23/12 x+10/12 =0 are x= 5/4 ,x= 2/3

Find the zeros of x^2-23/12 x+10/12 =0

The zeros of x^2-23/12 x+10/12 =0 are x= 5/4 ,x= 2/3

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x^{2} - \frac{23}{12} x + \frac{10}{12} = 0

x = \frac{5}{4}, x = \frac{2}{3}

Decimal Notation

x = 1.25, x = 0.66666 \dots

Solution steps

x^{2} - \frac{23}{12} x + \frac{10}{12} = 0

Multiply both sides by

12

12 x^{2} - 23 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 23 ) \pm ( - 23 ) ^{2} - 4 \cdot 12 \cdot 10}{2 \cdot 12}

(- 23)^{2} - 4 \cdot 12 \cdot 10 = 7

x_{1, 2} = \frac{- ( - 23 ) \pm 7}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 23 ) + 7}{2 \cdot 12}, x_{2} = \frac{- ( - 23 ) - 7}{2 \cdot 12}

x = \frac{- ( - 23 ) + 7}{2 \cdot 12} : \frac{5}{4}

x = \frac{- ( - 23 ) - 7}{2 \cdot 12} : \frac{2}{3}

The solutions to the quadratic equation are:

x = \frac{5}{4}, x = \frac{2}{3}

x^{2} + 14 x = - 2

7 x^{2} + 8 x - 22 = 0

x^{2} + 10 x + 16 = 0

(a x + b) (c x - d) = 4 x^{2} - 25

(5 x - 2)^{2} - (3 x + 1)^{2} - x^{2} = 60

What are the solutions to the equation x^2-23/12 x+10/12 =0 ?
The solutions to the equation x^2-23/12 x+10/12 =0 are x= 5/4 ,x= 2/3
Find the zeros of x^2-23/12 x+10/12 =0
The zeros of x^2-23/12 x+10/12 =0 are x= 5/4 ,x= 2/3