What are the solutions to the equation 2x^2+ax-3a^2=0 ?

The solutions to the equation 2x^2+ax-3a^2=0 are x=a,x=-(3a)/2

Find the zeros of 2x^2+ax-3a^2=0

The zeros of 2x^2+ax-3a^2=0 are x=a,x=-(3a)/2

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2 x^{2} + a x - 3 a^{2} = 0

x = a, x = - \frac{3 a}{2}

Solution steps

2 x^{2} + a x - 3 a^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- a \pm a ^{2} - 4 \cdot 2 ( - 3 a ^{2} )}{2 \cdot 2}

Simplify

a^{2} - 4 \cdot 2 (- 3 a^{2}) : 5 a

x_{1, 2} = \frac{- a \pm 5 a}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- a + 5 a}{2 \cdot 2}, x_{2} = \frac{- a - 5 a}{2 \cdot 2}

x = \frac{- a + 5 a}{2 \cdot 2} : a

x = \frac{- a - 5 a}{2 \cdot 2} : - \frac{3 a}{2}

The solutions to the quadratic equation are:

x = a, x = - \frac{3 a}{2}

7 x^{2} - 27 x + 1 = 5

x^{2} + 3 x + 1 = 0

x^{2} + 10 x + 14 = 0

x^{2} + 4 x = 0

(x^{2} - 12 x + 35) = 0

What are the solutions to the equation 2x^2+ax-3a^2=0 ?
The solutions to the equation 2x^2+ax-3a^2=0 are x=a,x=-(3a)/2
Find the zeros of 2x^2+ax-3a^2=0
The zeros of 2x^2+ax-3a^2=0 are x=a,x=-(3a)/2