What are the solutions to the equation x^2+10x-2000=0 ?

The solutions to the equation x^2+10x-2000=0 are x=40,x=-50

Find the zeros of x^2+10x-2000=0

The zeros of x^2+10x-2000=0 are x=40,x=-50

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x^{2} + 10 x - 2000 = 0

x = 40, x = - 50

Solution steps

x^{2} + 10 x - 2000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 2000 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 2000) = 90

x_{1, 2} = \frac{- 10 \pm 90}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 90}{2 \cdot 1}, x_{2} = \frac{- 10 - 90}{2 \cdot 1}

x = \frac{- 10 + 90}{2 \cdot 1} : 40

x = \frac{- 10 - 90}{2 \cdot 1} : - 50

The solutions to the quadratic equation are:

x = 40, x = - 50

x, (x^{2} + y^{2}) = 0

4 x^{2} + 38 x + 50 = 10 x - 35

x (x + 4) - 6 (x + 4) = 0

2 x^{2} - 2 x = 24

4 x^{2} - 4 x - 17 = 0

What are the solutions to the equation x^2+10x-2000=0 ?
The solutions to the equation x^2+10x-2000=0 are x=40,x=-50
Find the zeros of x^2+10x-2000=0
The zeros of x^2+10x-2000=0 are x=40,x=-50