What are the solutions to the equation 2x^2+7=8x ?

The solutions to the equation 2x^2+7=8x are x=(4+sqrt(2))/2 ,x=(4-sqrt(2))/2

Find the zeros of 2x^2+7=8x

The zeros of 2x^2+7=8x are x=(4+sqrt(2))/2 ,x=(4-sqrt(2))/2

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2 x^{2} + 7 = 8 x

x = \frac{4 + 2}{2}, x = \frac{4 - 2}{2}

Decimal Notation

x = 2.70710 \dots, x = 1.29289 \dots

Solution steps

2 x^{2} + 7 = 8 x

Move

8 x

to the left side

2 x^{2} + 7 - 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 8 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 \cdot 7}{2 \cdot 2}

(- 8)^{2} - 4 \cdot 2 \cdot 7 = 22

x_{1, 2} = \frac{- ( - 8 ) \pm 2 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 2}{2 \cdot 2}, x_{2} = \frac{- ( - 8 ) - 2 2}{2 \cdot 2}

x = \frac{- ( - 8 ) + 2 2}{2 \cdot 2} : \frac{4 + 2}{2}

x = \frac{- ( - 8 ) - 2 2}{2 \cdot 2} : \frac{4 - 2}{2}

The solutions to the quadratic equation are:

x = \frac{4 + 2}{2}, x = \frac{4 - 2}{2}

3 x^{2} + 12 x - 15 x = 0

- x^{2} + 11 x - 10 = 0

(w + 7) (w - 2) = 0

a^{2} x^{2} + b^{2} = 0

y, x = 4 y^{2}

What are the solutions to the equation 2x^2+7=8x ?
The solutions to the equation 2x^2+7=8x are x=(4+sqrt(2))/2 ,x=(4-sqrt(2))/2
Find the zeros of 2x^2+7=8x
The zeros of 2x^2+7=8x are x=(4+sqrt(2))/2 ,x=(4-sqrt(2))/2