What are the solutions to the equation -16t^2+1354=0 ?

The solutions to the equation -16t^2+1354=0 are t=(sqrt(677))/(2sqrt(2)),t=-(sqrt(677))/(2sqrt(2))

Find the zeros of -16t^2+1354=0

The zeros of -16t^2+1354=0 are t=(sqrt(677))/(2sqrt(2)),t=-(sqrt(677))/(2sqrt(2))

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- 16 t^{2} + 1354 = 0

t = \frac{677}{2 2}, t = - \frac{677}{2 2}

Decimal Notation

t = 9.19918 \dots, t = - 9.19918 \dots

Solution steps

- 16 t^{2} + 1354 = 0

Move

1354

to the right side

- 16 t^{2} = - 1354

Divide both sides by

- 16

t^{2} = \frac{677}{8}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = \frac{677}{8}, t = - \frac{677}{8}

\frac{677}{8} = \frac{677}{2 2}

- \frac{677}{8} = - \frac{677}{2 2}

t = \frac{677}{2 2}, t = - \frac{677}{2 2}

\frac{4}{52} \cdot \frac{4}{52}

6 x^{2} - 384

- \frac{\frac{2}{3}}{( - \frac{8}{7} )}

\frac{12 !}{( 12 - 2 ) !} + \frac{13 !}{( 13 - 4 ) !}

\frac{1}{x - 2} + 1 \geq 0

What are the solutions to the equation -16t^2+1354=0 ?
The solutions to the equation -16t^2+1354=0 are t=(sqrt(677))/(2sqrt(2)),t=-(sqrt(677))/(2sqrt(2))
Find the zeros of -16t^2+1354=0
The zeros of -16t^2+1354=0 are t=(sqrt(677))/(2sqrt(2)),t=-(sqrt(677))/(2sqrt(2))