What are the solutions to the equation (1-x)(3-x)=8 ?

The solutions to the equation (1-x)(3-x)=8 are x=5,x=-1

Find the zeros of (1-x)(3-x)=8

The zeros of (1-x)(3-x)=8 are x=5,x=-1

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(1 - x) (3 - x) = 8

x = 5, x = - 1

Solution steps

(1 - x) (3 - x) = 8

Expand

(1 - x) (3 - x) : 3 - 4 x + x^{2}

3 - 4 x + x^{2} = 8

Move

8

to the left side

x^{2} - 4 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 5) = 6

x_{1, 2} = \frac{- ( - 4 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 6}{2 \cdot 1}

x = \frac{- ( - 4 ) + 6}{2 \cdot 1} : 5

x = \frac{- ( - 4 ) - 6}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 5, x = - 1

5 x^{2} - 7 x - 10 = 0

0.012 q^{2} + 50 = 60

- 3 x^{2} + 114 x + 240 = 0

r, A = 2 π r h + 2 π r^{2}

x, 9 x^{2} - 5 x - 1 = 0

What are the solutions to the equation (1-x)(3-x)=8 ?
The solutions to the equation (1-x)(3-x)=8 are x=5,x=-1
Find the zeros of (1-x)(3-x)=8
The zeros of (1-x)(3-x)=8 are x=5,x=-1