What are the solutions to the equation w^2-2w-37=7 ?

The solutions to the equation w^2-2w-37=7 are w=1+3sqrt(5),w=1-3sqrt(5)

Find the zeros of w^2-2w-37=7

The zeros of w^2-2w-37=7 are w=1+3sqrt(5),w=1-3sqrt(5)

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w^{2} - 2 w - 37 = 7

w = 1 + 35, w = 1 - 35

Decimal Notation

w = 7.70820 \dots, w = - 5.70820 \dots

Solution steps

w^{2} - 2 w - 37 = 7

Move

7

to the left side

w^{2} - 2 w - 44 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 44 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 44) = 65

w_{1, 2} = \frac{- ( - 2 ) \pm 6 5}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 2 ) + 6 5}{2 \cdot 1}, w_{2} = \frac{- ( - 2 ) - 6 5}{2 \cdot 1}

w = \frac{- ( - 2 ) + 6 5}{2 \cdot 1} : 1 + 35

w = \frac{- ( - 2 ) - 6 5}{2 \cdot 1} : 1 - 35

The solutions to the quadratic equation are:

w = 1 + 35, w = 1 - 35

0 = - 3 x^{2} + 12 x - 9

1600 + 1500 x = 1600 x - x^{2}

(x - 4) (x + 2) + 8 x = 3 (x^{2} - 5) - 1

x^{2} + 2 x = 3

c (x) = 2000 + 100 x - 0.1 x^{2}

What are the solutions to the equation w^2-2w-37=7 ?
The solutions to the equation w^2-2w-37=7 are w=1+3sqrt(5),w=1-3sqrt(5)
Find the zeros of w^2-2w-37=7
The zeros of w^2-2w-37=7 are w=1+3sqrt(5),w=1-3sqrt(5)