What are the solutions to the equation -1/2 x^2+x+4=0 ?

The solutions to the equation -1/2 x^2+x+4=0 are x=-2,x=4

Find the zeros of -1/2 x^2+x+4=0

The zeros of -1/2 x^2+x+4=0 are x=-2,x=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- \frac{1}{2} x^{2} + x + 4 = 0

x = - 2, x = 4

Solution steps

- \frac{1}{2} x^{2} + x + 4 = 0

Multiply both sides by

2

- x^{2} + 2 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 1 ) \cdot 8}{2 ( - 1 )}

2^{2} - 4 (- 1) \cdot 8 = 6

x_{1, 2} = \frac{- 2 \pm 6}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 2 + 6}{2 ( - 1 )}, x_{2} = \frac{- 2 - 6}{2 ( - 1 )}

x = \frac{- 2 + 6}{2 ( - 1 )} : - 2

x = \frac{- 2 - 6}{2 ( - 1 )} : 4

The solutions to the quadratic equation are:

x = - 2, x = 4

2 x^{2} - x = 0

x^{2} = 16 x - 63

p, 0 = p + c p (1 - p) - e p (1 - p)

15 = - x^{2} + 8 x

5 x^{2} - 6 x + 7 = 0

What are the solutions to the equation -1/2 x^2+x+4=0 ?
The solutions to the equation -1/2 x^2+x+4=0 are x=-2,x=4
Find the zeros of -1/2 x^2+x+4=0
The zeros of -1/2 x^2+x+4=0 are x=-2,x=4