What are the solutions to the equation 3^2=sqrt(5)^2+x^2 ?

The solutions to the equation 3^2=sqrt(5)^2+x^2 are x=2,x=-2

Find the zeros of 3^2=sqrt(5)^2+x^2

The zeros of 3^2=sqrt(5)^2+x^2 are x=2,x=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3^{2} = 5^{2} + x^{2}

x = 2, x = - 2

Solution steps

3^{2} = (5)^{2} + x^{2}

Switch sides

(5)^{2} + x^{2} = 3^{2}

Move

5^{2}

to the right side

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

s^{2} + 15 s + 56 = 0

x^{2} - 13 x + 1 = 0

3 u^{2} + 18 u = 0

0.585 = - 0.26 x^{2} + 0.93 x + 0.8791

24 = 3 x^{2} + 34 x

What are the solutions to the equation 3^2=sqrt(5)^2+x^2 ?
The solutions to the equation 3^2=sqrt(5)^2+x^2 are x=2,x=-2
Find the zeros of 3^2=sqrt(5)^2+x^2
The zeros of 3^2=sqrt(5)^2+x^2 are x=2,x=-2