What are the solutions to the equation 3=3x^2+8x ?

The solutions to the equation 3=3x^2+8x are x= 1/3 ,x=-3

Find the zeros of 3=3x^2+8x

The zeros of 3=3x^2+8x are x= 1/3 ,x=-3

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3 = 3 x^{2} + 8 x

x = \frac{1}{3}, x = - 3

Decimal Notation

x = 0.33333 \dots, x = - 3

Solution steps

3 = 3 x^{2} + 8 x

Switch sides

3 x^{2} + 8 x = 3

Move

3

to the left side

3 x^{2} + 8 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 3 ( - 3 )}{2 \cdot 3}

8^{2} - 4 \cdot 3 (- 3) = 10

x_{1, 2} = \frac{- 8 \pm 10}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 8 + 10}{2 \cdot 3}, x_{2} = \frac{- 8 - 10}{2 \cdot 3}

x = \frac{- 8 + 10}{2 \cdot 3} : \frac{1}{3}

x = \frac{- 8 - 10}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - 3

1 x^{2} + 1 x - 2 = 0

1 - 0.5 x + 0.5 x^{2} = 0

0 = (x - 3)^{2} - 1

2 (x - 2)^{2} + 3 = 0

x^{2} + 2 x - 8 = 0

What are the solutions to the equation 3=3x^2+8x ?
The solutions to the equation 3=3x^2+8x are x= 1/3 ,x=-3
Find the zeros of 3=3x^2+8x
The zeros of 3=3x^2+8x are x= 1/3 ,x=-3