What are the solutions to the equation completesquare x^2-4x-7=0 ?

The solutions to the equation completesquare x^2-4x-7=0 are x=sqrt(11)+2,x=-sqrt(11)+2

Find the zeros of completesquare x^2-4x-7=0

The zeros of completesquare x^2-4x-7=0 are x=sqrt(11)+2,x=-sqrt(11)+2

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x^{2} - 4 x - 7 = 0

x = 11 + 2, x = - 11 + 2

Decimal Notation

x = 5.31662 \dots, x = - 1.31662 \dots

Solution steps

x^{2} - 4 x - 7 = 0

Move

7

to the right side

x^{2} - 4 x = 7

Rewrite in the form

(x + a)^{2} = b

(x - 2)^{2} = 11

For

the solutions are

f (x) = a, - a

Solve

x - 2 = 11 : x = 11 + 2

Solve

x - 2 = - 11 : x = - 11 + 2

The solutions to the quadratic equation are:

x = 11 + 2, x = - 11 + 2

x^{2} + 10 x + 23 = 0

x, z = 2 x + 4 y - x^{2} - y^{2} - 3

x^{2} + 4 x = 95

x^{2} + 6 x - 71 = 0

y, x = \frac{1}{2} y^{2} - z

What are the solutions to the equation completesquare x^2-4x-7=0 ?
The solutions to the equation completesquare x^2-4x-7=0 are x=sqrt(11)+2,x=-sqrt(11)+2
Find the zeros of completesquare x^2-4x-7=0
The zeros of completesquare x^2-4x-7=0 are x=sqrt(11)+2,x=-sqrt(11)+2