What are the solutions to the equation (x+4)(2x-1)=0 ?

The solutions to the equation (x+4)(2x-1)=0 are x=-4,x= 1/2

Find the zeros of (x+4)(2x-1)=0

The zeros of (x+4)(2x-1)=0 are x=-4,x= 1/2

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(x + 4) (2 x - 1) = 0

x = - 4, x = \frac{1}{2}

Decimal Notation

x = - 4, x = 0.5

Solution steps

(x + 4) (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 4 = 0 or 2 x - 1 = 0

Solve

x + 4 = 0 : x = - 4

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions to the quadratic equation are:

x = - 4, x = \frac{1}{2}

x^{2} + 10 x - 96 = 0

4 x^{2} - 10 x - 5 = 0

\frac{2}{7} x^{2} + \frac{7}{2} x = 0

t, x = t^{2}

2 m^{2} + m - 8 = 0

What are the solutions to the equation (x+4)(2x-1)=0 ?
The solutions to the equation (x+4)(2x-1)=0 are x=-4,x= 1/2
Find the zeros of (x+4)(2x-1)=0
The zeros of (x+4)(2x-1)=0 are x=-4,x= 1/2