What are the solutions to the equation 7-9x+4x^2=0 ?

The solutions to the equation 7-9x+4x^2=0 are x= 9/8+i(sqrt(31))/8 ,x= 9/8-i(sqrt(31))/8

Find the zeros of 7-9x+4x^2=0

The zeros of 7-9x+4x^2=0 are x= 9/8+i(sqrt(31))/8 ,x= 9/8-i(sqrt(31))/8

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7 - 9 x + 4 x^{2} = 0

x = \frac{9}{8} + i \frac{31}{8}, x = \frac{9}{8} - i \frac{31}{8}

Solution steps

7 - 9 x + 4 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 9 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 4 \cdot 7}{2 \cdot 4}

Simplify

(- 9)^{2} - 4 \cdot 4 \cdot 7 : 31 i

x_{1, 2} = \frac{- ( - 9 ) \pm 31 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 31 i}{2 \cdot 4}, x_{2} = \frac{- ( - 9 ) - 31 i}{2 \cdot 4}

x = \frac{- ( - 9 ) + 31 i}{2 \cdot 4} : \frac{9}{8} + i \frac{31}{8}

x = \frac{- ( - 9 ) - 31 i}{2 \cdot 4} : \frac{9}{8} - i \frac{31}{8}

The solutions to the quadratic equation are:

x = \frac{9}{8} + i \frac{31}{8}, x = \frac{9}{8} - i \frac{31}{8}

s^{2} + 40 s + 1600 = 0

8 - y^{2} = 4 y + 12

x^{2} + (20 - x)^{2} = 202

9 x^{2} = 9 x - 2

6 x^{2} + 0 x - 15 = 0

What are the solutions to the equation 7-9x+4x^2=0 ?
The solutions to the equation 7-9x+4x^2=0 are x= 9/8+i(sqrt(31))/8 ,x= 9/8-i(sqrt(31))/8
Find the zeros of 7-9x+4x^2=0
The zeros of 7-9x+4x^2=0 are x= 9/8+i(sqrt(31))/8 ,x= 9/8-i(sqrt(31))/8