What are the solutions to the equation 16-5x^2=-21x^2+25 ?

The solutions to the equation 16-5x^2=-21x^2+25 are x= 3/4 ,x=-3/4

Find the zeros of 16-5x^2=-21x^2+25

The zeros of 16-5x^2=-21x^2+25 are x= 3/4 ,x=-3/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

16 - 5 x^{2} = - 21 x^{2} + 25

x = \frac{3}{4}, x = - \frac{3}{4}

Decimal Notation

x = 0.75, x = - 0.75

Solution steps

16 - 5 x^{2} = - 21 x^{2} + 25

Move

16

to the right side

- 5 x^{2} = - 21 x^{2} + 9

Move

21 x^{2}

to the left side

16 x^{2} = 9

Divide both sides by

16

x^{2} = \frac{9}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{9}{16}, x = - \frac{9}{16}

\frac{9}{16} = \frac{3}{4}

- \frac{9}{16} = - \frac{3}{4}

x = \frac{3}{4}, x = - \frac{3}{4}

0 = - (x - 1)^{2} + 4

2 x^{2} + b x - 3 = 0

4 x^{2} + 14 x - 8 = 0

- 3 x^{2} + 17 x = 10

3 x^{2} - 5 = 103

What are the solutions to the equation 16-5x^2=-21x^2+25 ?
The solutions to the equation 16-5x^2=-21x^2+25 are x= 3/4 ,x=-3/4
Find the zeros of 16-5x^2=-21x^2+25
The zeros of 16-5x^2=-21x^2+25 are x= 3/4 ,x=-3/4