What are the solutions to the equation x^2+12^2=20^2 ?

The solutions to the equation x^2+12^2=20^2 are x=16,x=-16

Find the zeros of x^2+12^2=20^2

The zeros of x^2+12^2=20^2 are x=16,x=-16

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x^{2} + 1 2^{2} = 2 0^{2}

x = 16, x = - 16

Solution steps

x^{2} + 1 2^{2} = 2 0^{2}

Move

1 2^{2}

to the right side

x^{2} = 256

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 256, x = - 256

256 = 16

- 256 = - 16

x = 16, x = - 16

- 2 x + 4 x^{2} + 17 = - 5 x

x, f = x^{2} y + 2 x + 3 y

3 a^{2} - 6 a - 5 = 0

v^{2} + 4 v - 12 = 0

h^{2} - 31 h = 0

What are the solutions to the equation x^2+12^2=20^2 ?
The solutions to the equation x^2+12^2=20^2 are x=16,x=-16
Find the zeros of x^2+12^2=20^2
The zeros of x^2+12^2=20^2 are x=16,x=-16