What are the solutions to the equation 3(x+1)^2-22=5 ?

The solutions to the equation 3(x+1)^2-22=5 are x=2,x=-4

Find the zeros of 3(x+1)^2-22=5

The zeros of 3(x+1)^2-22=5 are x=2,x=-4

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3 (x + 1)^{2} - 22 = 5

x = 2, x = - 4

Solution steps

3 (x + 1)^{2} - 22 = 5

Move

22

to the right side

3 (x + 1)^{2} = 27

Divide both sides by

3

(x + 1)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 9 : x = 2

Solve

x + 1 = - 9 : x = - 4

The solutions to the quadratic equation are:

x = 2, x = - 4

- \frac{2}{3} + 1

3 x + 10 \leq - 2

\frac{u}{2} - 1 < 1

1 < x \leq 6

What are the solutions to the equation 3(x+1)^2-22=5 ?
The solutions to the equation 3(x+1)^2-22=5 are x=2,x=-4
Find the zeros of 3(x+1)^2-22=5
The zeros of 3(x+1)^2-22=5 are x=2,x=-4