What are the solutions to the equation -x^2+2x-24=0 ?

The solutions to the equation -x^2+2x-24=0 are x=1-sqrt(23)i,x=1+sqrt(23)i

Find the zeros of -x^2+2x-24=0

The zeros of -x^2+2x-24=0 are x=1-sqrt(23)i,x=1+sqrt(23)i

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- x^{2} + 2 x - 24 = 0

x = 1 - 23 i, x = 1 + 23 i

Solution steps

- x^{2} + 2 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 1 ) ( - 24 )}{2 ( - 1 )}

Simplify

2^{2} - 4 (- 1) (- 24) : 223 i

x_{1, 2} = \frac{- 2 \pm 2 23 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 2 + 2 23 i}{2 ( - 1 )}, x_{2} = \frac{- 2 - 2 23 i}{2 ( - 1 )}

x = \frac{- 2 + 2 23 i}{2 ( - 1 )} : 1 - 23 i

x = \frac{- 2 - 2 23 i}{2 ( - 1 )} : 1 + 23 i

The solutions to the quadratic equation are:

x = 1 - 23 i, x = 1 + 23 i

0 = - x^{2} + 8 x - 15

x^{2} - 3 x + 2 = 12

(x) = x^{2} + 1

x, \frac{( x ^{(2)} + y ^{3} )}{y} - 4 x^{2} y = 4

x^{2} - 20 x = 6 x^{2} - 2 x + 20

What are the solutions to the equation -x^2+2x-24=0 ?
The solutions to the equation -x^2+2x-24=0 are x=1-sqrt(23)i,x=1+sqrt(23)i
Find the zeros of -x^2+2x-24=0
The zeros of -x^2+2x-24=0 are x=1-sqrt(23)i,x=1+sqrt(23)i