What are the solutions to the equation 4z^2-z-3=0 ?

The solutions to the equation 4z^2-z-3=0 are z=1,z=-3/4

Find the zeros of 4z^2-z-3=0

The zeros of 4z^2-z-3=0 are z=1,z=-3/4

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4 z^{2} - z - 3 = 0

z = 1, z = - \frac{3}{4}

Decimal Notation

z = 1, z = - 0.75

Solution steps

4 z^{2} - z - 3 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

(- 1)^{2} - 4 \cdot 4 (- 3) = 7

z_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 \cdot 4}

Separate the solutions

z_{1} = \frac{- ( - 1 ) + 7}{2 \cdot 4}, z_{2} = \frac{- ( - 1 ) - 7}{2 \cdot 4}

z = \frac{- ( - 1 ) + 7}{2 \cdot 4} : 1

z = \frac{- ( - 1 ) - 7}{2 \cdot 4} : - \frac{3}{4}

The solutions to the quadratic equation are:

z = 1, z = - \frac{3}{4}

x^{2} - 3.5 x + 2.5 = 0

20 x^{2} + 9 x - 18 = 0

(x + 5) (3 x - 5) = 0

b^{2} - 4 b = 0

x^{2} - 6 = 58

What are the solutions to the equation 4z^2-z-3=0 ?
The solutions to the equation 4z^2-z-3=0 are z=1,z=-3/4
Find the zeros of 4z^2-z-3=0
The zeros of 4z^2-z-3=0 are z=1,z=-3/4