What are the solutions to the equation x^2-6=-x ?

The solutions to the equation x^2-6=-x are x=2,x=-3

Find the zeros of x^2-6=-x

The zeros of x^2-6=-x are x=2,x=-3

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x^{2} - 6 = - x

x = 2, x = - 3

Solution steps

x^{2} - 6 = - x

Move

x

to the left side

x^{2} - 6 + x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 6) = 5

x_{1, 2} = \frac{- 1 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 5}{2 \cdot 1}, x_{2} = \frac{- 1 - 5}{2 \cdot 1}

x = \frac{- 1 + 5}{2 \cdot 1} : 2

x = \frac{- 1 - 5}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 2, x = - 3

- x^{2} - 4 x - 4 = - 2

3 x^{2} + 24 x + 50

x, f = x^{2} - 4 y

3 x^{2} + 15 x + 12 = 0

4 x^{2} - 24 x + 39 = 0

What are the solutions to the equation x^2-6=-x ?
The solutions to the equation x^2-6=-x are x=2,x=-3
Find the zeros of x^2-6=-x
The zeros of x^2-6=-x are x=2,x=-3