What are the solutions to the equation 0=x^2+2x-7 ?

The solutions to the equation 0=x^2+2x-7 are x=-1+2sqrt(2),x=-1-2sqrt(2)

Find the zeros of 0=x^2+2x-7

The zeros of 0=x^2+2x-7 are x=-1+2sqrt(2),x=-1-2sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = x^{2} + 2 x - 7

x = - 1 + 22, x = - 1 - 22

Decimal Notation

x = 1.82842 \dots, x = - 3.82842 \dots

Solution steps

0 = x^{2} + 2 x - 7

Switch sides

x^{2} + 2 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 7) = 42

x_{1, 2} = \frac{- 2 \pm 4 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 4 2}{2 \cdot 1}, x_{2} = \frac{- 2 - 4 2}{2 \cdot 1}

x = \frac{- 2 + 4 2}{2 \cdot 1} : - 1 + 22

x = \frac{- 2 - 4 2}{2 \cdot 1} : - 1 - 22

The solutions to the quadratic equation are:

x = - 1 + 22, x = - 1 - 22

5 x^{2} - 10 x + 2 = 0

y = 2.49 \cdot 1 0^{- 3} (1 - \frac{0.5714 - 500 y}{- 2})^{2}

n^{2} + n - 2 = 0

x^{2} = 4 - x^{2}

x, 4 x^{2} + y^{2} + 4 z^{2} - 4 y - 24 z + 36 = 0

What are the solutions to the equation 0=x^2+2x-7 ?
The solutions to the equation 0=x^2+2x-7 are x=-1+2sqrt(2),x=-1-2sqrt(2)
Find the zeros of 0=x^2+2x-7
The zeros of 0=x^2+2x-7 are x=-1+2sqrt(2),x=-1-2sqrt(2)