What are the solutions to the equation 9x^2+3x+3=0 ?

The solutions to the equation 9x^2+3x+3=0 are x=-1/6+i(sqrt(11))/6 ,x=-1/6-i(sqrt(11))/6

Find the zeros of 9x^2+3x+3=0

The zeros of 9x^2+3x+3=0 are x=-1/6+i(sqrt(11))/6 ,x=-1/6-i(sqrt(11))/6

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9 x^{2} + 3 x + 3 = 0

x = - \frac{1}{6} + i \frac{11}{6}, x = - \frac{1}{6} - i \frac{11}{6}

Solution steps

9 x^{2} + 3 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 9 \cdot 3}{2 \cdot 9}

Simplify

3^{2} - 4 \cdot 9 \cdot 3 : 311 i

x_{1, 2} = \frac{- 3 \pm 3 11 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 3 + 3 11 i}{2 \cdot 9}, x_{2} = \frac{- 3 - 3 11 i}{2 \cdot 9}

x = \frac{- 3 + 3 11 i}{2 \cdot 9} : - \frac{1}{6} + i \frac{11}{6}

x = \frac{- 3 - 3 11 i}{2 \cdot 9} : - \frac{1}{6} - i \frac{11}{6}

The solutions to the quadratic equation are:

x = - \frac{1}{6} + i \frac{11}{6}, x = - \frac{1}{6} - i \frac{11}{6}

x (x + 2) = - 10

z^{2} = 12

z^{2} = 36

(x + 1) (x - 1) = 2 x

(x - 3) (x + 3) + 9 = 0

What are the solutions to the equation 9x^2+3x+3=0 ?
The solutions to the equation 9x^2+3x+3=0 are x=-1/6+i(sqrt(11))/6 ,x=-1/6-i(sqrt(11))/6
Find the zeros of 9x^2+3x+3=0
The zeros of 9x^2+3x+3=0 are x=-1/6+i(sqrt(11))/6 ,x=-1/6-i(sqrt(11))/6