What are the solutions to the equation 12^2=10^2+x^2 ?

The solutions to the equation 12^2=10^2+x^2 are x=2sqrt(11),x=-2sqrt(11)

Find the zeros of 12^2=10^2+x^2

The zeros of 12^2=10^2+x^2 are x=2sqrt(11),x=-2sqrt(11)

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1 2^{2} = 1 0^{2} + x^{2}

x = 211, x = - 211

Decimal Notation

x = 6.63324 \dots, x = - 6.63324 \dots

Solution steps

1 2^{2} = 1 0^{2} + x^{2}

Switch sides

1 0^{2} + x^{2} = 1 2^{2}

Move

1 0^{2}

to the right side

x^{2} = 44

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 44, x = - 44

44 = 211

- 44 = - 211

x = 211, x = - 211

(2 x + 6) (x + 2) = 144

0.1 x^{2} = 100

x, x^{2} + y^{2} + z^{2} - 8 x + 8 y - 6 z - 9 = 0

30 x^{2} + 17 a x - 21 a^{2} = 0

(x + 7) (x - 18) = 0

What are the solutions to the equation 12^2=10^2+x^2 ?
The solutions to the equation 12^2=10^2+x^2 are x=2sqrt(11),x=-2sqrt(11)
Find the zeros of 12^2=10^2+x^2
The zeros of 12^2=10^2+x^2 are x=2sqrt(11),x=-2sqrt(11)