What are the solutions to the equation x^2+16x+19=4 ?

The solutions to the equation x^2+16x+19=4 are x=-1,x=-15

Find the zeros of x^2+16x+19=4

The zeros of x^2+16x+19=4 are x=-1,x=-15

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x^{2} + 16 x + 19 = 4

x = - 1, x = - 15

Solution steps

x^{2} + 16 x + 19 = 4

Move

4

to the left side

x^{2} + 16 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 15 = 14

x_{1, 2} = \frac{- 16 \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 14}{2 \cdot 1}, x_{2} = \frac{- 16 - 14}{2 \cdot 1}

x = \frac{- 16 + 14}{2 \cdot 1} : - 1

x = \frac{- 16 - 14}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

x = - 1, x = - 15

x (x + 13) = 30

9 x^{2} = 24 x - 17

x^{2} + 6 x = - 8

x, F = x^{2} - y^{2} z + z^{2}

a, y = 16 a^{2} - 10 a + 1

What are the solutions to the equation x^2+16x+19=4 ?
The solutions to the equation x^2+16x+19=4 are x=-1,x=-15
Find the zeros of x^2+16x+19=4
The zeros of x^2+16x+19=4 are x=-1,x=-15