What are the solutions to the equation 10x^2+5(4x+2)=0 ?

The solutions to the equation 10x^2+5(4x+2)=0 are x=-1

Find the zeros of 10x^2+5(4x+2)=0

The zeros of 10x^2+5(4x+2)=0 are x=-1

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10 x^{2} + 5 (4 x + 2) = 0

x = - 1

Solution steps

10 x^{2} + 5 (4 x + 2) = 0

Expand

10 x^{2} + 5 (4 x + 2) : 10 x^{2} + 20 x + 10

10 x^{2} + 20 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 10 \cdot 10}{2 \cdot 10}

2 0^{2} - 4 \cdot 10 \cdot 10 = 0

x_{1, 2} = \frac{- 20 \pm 0}{2 \cdot 10}

x = \frac{- 20}{2 \cdot 10}

\frac{- 20}{2 \cdot 10} = - 1

x = - 1

The solution to the quadratic equation is:

x = - 1

y^{2} + y + 2 y = 0

x^{2} + 2 1^{2} = 2 9^{2}

- 2 x^{2} - 10 x - 12 = 0

9 x^{2} - 196 = 0

b^{2} - 5 b = 0

What are the solutions to the equation 10x^2+5(4x+2)=0 ?
The solutions to the equation 10x^2+5(4x+2)=0 are x=-1
Find the zeros of 10x^2+5(4x+2)=0
The zeros of 10x^2+5(4x+2)=0 are x=-1