What are the solutions to the equation k^2=1 ?

The solutions to the equation k^2=1 are k=1,k=-1

Find the zeros of k^2=1

The zeros of k^2=1 are k=1,k=-1

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k^{2} = 1

k = 1, k = - 1

Solution steps

k^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

k = 1, k = - 1

1 = 1

- 1 = - 1

k = 1, k = - 1

\frac{7 π}{2} + \frac{π}{2}

ln (x + 1) - ln (x - 1)

7 (2 x + 4) = 4 (7 - 2 x)

x^{2} - 16

w^{6} - z^{6}

What are the solutions to the equation k^2=1 ?
The solutions to the equation k^2=1 are k=1,k=-1
Find the zeros of k^2=1
The zeros of k^2=1 are k=1,k=-1