What are the solutions to the equation 4x=x^2+3 ?

The solutions to the equation 4x=x^2+3 are x=3,x=1

Find the zeros of 4x=x^2+3

The zeros of 4x=x^2+3 are x=3,x=1

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4 x = x^{2} + 3

x = 3, x = 1

Solution steps

4 x = x^{2} + 3

Switch sides

x^{2} + 3 = 4 x

Move

4 x

to the left side

x^{2} + 3 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 4 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 3 = 2

x_{1, 2} = \frac{- ( - 4 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2}{2 \cdot 1} : 3

x = \frac{- ( - 4 ) - 2}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 3, x = 1

x, 2 x^{2} y = x + y

6 x = 3 x^{2}

1 1^{2} + 9^{2} = x^{2}

x^{2} - 3 x + 10 = 8

3 (x - 1)^{2} + 10 = 0

What are the solutions to the equation 4x=x^2+3 ?
The solutions to the equation 4x=x^2+3 are x=3,x=1
Find the zeros of 4x=x^2+3
The zeros of 4x=x^2+3 are x=3,x=1