What are the solutions to the equation 20-5x^2=0 ?

The solutions to the equation 20-5x^2=0 are x=2,x=-2

Find the zeros of 20-5x^2=0

The zeros of 20-5x^2=0 are x=2,x=-2

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20 - 5 x^{2} = 0

x = 2, x = - 2

Solution steps

20 - 5 x^{2} = 0

Move

20

to the right side

- 5 x^{2} = - 20

Divide both sides by

- 5

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

x (x + 1) + 3 (x - 2)^{2} = (x - 1)^{2}

\frac{x}{4} = \frac{x ^{2}}{9}

3 t^{2} - 24 t = 0

x, 5 x^{2} + 6 x y + 5 y^{2} - 4 x + 4 y - 4 = 0

5 n^{2} + 4 = - 1 + 2 n^{2} + n

What are the solutions to the equation 20-5x^2=0 ?
The solutions to the equation 20-5x^2=0 are x=2,x=-2
Find the zeros of 20-5x^2=0
The zeros of 20-5x^2=0 are x=2,x=-2