What are the solutions to the equation x^2+8x+15=(x+3) ?

The solutions to the equation x^2+8x+15=(x+3) are x=-3,x=-4

Find the zeros of x^2+8x+15=(x+3)

The zeros of x^2+8x+15=(x+3) are x=-3,x=-4

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x^{2} + 8 x + 15 = (x + 3)

x = - 3, x = - 4

Solution steps

x^{2} + 8 x + 15 = (x + 3)

Refine

x^{2} + 8 x + 15 = x + 3

Move

3

to the left side

x^{2} + 8 x + 12 = x

Move

x

to the left side

x^{2} + 7 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 12 = 1

x_{1, 2} = \frac{- 7 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 1}{2 \cdot 1}, x_{2} = \frac{- 7 - 1}{2 \cdot 1}

x = \frac{- 7 + 1}{2 \cdot 1} : - 3

x = \frac{- 7 - 1}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = - 3, x = - 4

(2 x + 3)^{2} = (x - 2)^{2}

x^{2} + 9^{2} = 1 2^{2}

9 x^{2} + 2 x = 2 x^{2} - 6 x

(x + 10)^{2} = 200

x^{2} - 20 x + 100 = 40

What are the solutions to the equation x^2+8x+15=(x+3) ?
The solutions to the equation x^2+8x+15=(x+3) are x=-3,x=-4
Find the zeros of x^2+8x+15=(x+3)
The zeros of x^2+8x+15=(x+3) are x=-3,x=-4