What are the solutions to the equation solvefor y,y^2=x^4(1-x^2) ?

The solutions to the equation solvefor y,y^2=x^4(1-x^2) are y=x^2sqrt(1-x^2),y=-x^2sqrt(1-x^2)

Find the zeros of solvefor y,y^2=x^4(1-x^2)

The zeros of solvefor y,y^2=x^4(1-x^2) are y=x^2sqrt(1-x^2),y=-x^2sqrt(1-x^2)

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solve for

y, y^{2} = x^{4} (1 - x^{2})

y = x^{2} 1 - x^{2}, y = - x^{2} 1 - x^{2}

Solution steps

y^{2} = x^{4} (1 - x^{2})

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = x^{4} (1 - x^{2}), y = - x^{4} (1 - x^{2})

Simplify

x^{4} (1 - x^{2}) : x^{2} 1 - x^{2}

Simplify

- x^{4} (1 - x^{2}) : - x^{2} 1 - x^{2}

y = x^{2} 1 - x^{2}, y = - x^{2} 1 - x^{2}

3 y^{2} = 432

3 = \frac{5}{2} (x - 3 - 0.5)^{2}

x, x^{2} + y^{2} = - 2

x, x^{2} + y^{2} = - 9

x^{2} + 5 x = 0

What are the solutions to the equation solvefor y,y^2=x^4(1-x^2) ?
The solutions to the equation solvefor y,y^2=x^4(1-x^2) are y=x^2sqrt(1-x^2),y=-x^2sqrt(1-x^2)
Find the zeros of solvefor y,y^2=x^4(1-x^2)
The zeros of solvefor y,y^2=x^4(1-x^2) are y=x^2sqrt(1-x^2),y=-x^2sqrt(1-x^2)