What are the solutions to the equation 0=2x^2-6x-1 ?

The solutions to the equation 0=2x^2-6x-1 are x=(3+sqrt(11))/2 ,x=(3-sqrt(11))/2

Find the zeros of 0=2x^2-6x-1

The zeros of 0=2x^2-6x-1 are x=(3+sqrt(11))/2 ,x=(3-sqrt(11))/2

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0 = 2 x^{2} - 6 x - 1

x = \frac{3 + 11}{2}, x = \frac{3 - 11}{2}

Decimal Notation

x = 3.15831 \dots, x = - 0.15831 \dots

Solution steps

0 = 2 x^{2} - 6 x - 1

Switch sides

2 x^{2} - 6 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

(- 6)^{2} - 4 \cdot 2 (- 1) = 211

x_{1, 2} = \frac{- ( - 6 ) \pm 2 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 11}{2 \cdot 2}, x_{2} = \frac{- ( - 6 ) - 2 11}{2 \cdot 2}

x = \frac{- ( - 6 ) + 2 11}{2 \cdot 2} : \frac{3 + 11}{2}

x = \frac{- ( - 6 ) - 2 11}{2 \cdot 2} : \frac{3 - 11}{2}

The solutions to the quadratic equation are:

x = \frac{3 + 11}{2}, x = \frac{3 - 11}{2}

u^{2} = - 121

(m^{2} - 1) = 0

128 = - 16 t^{2} + 96 t

x^{2} + 48 x - 100 = 0

11 k^{2} = 20 + 3 k

What are the solutions to the equation 0=2x^2-6x-1 ?
The solutions to the equation 0=2x^2-6x-1 are x=(3+sqrt(11))/2 ,x=(3-sqrt(11))/2
Find the zeros of 0=2x^2-6x-1
The zeros of 0=2x^2-6x-1 are x=(3+sqrt(11))/2 ,x=(3-sqrt(11))/2