What are the solutions to the equation 15x^2-60x=0 ?

The solutions to the equation 15x^2-60x=0 are x=4,x=0

Find the zeros of 15x^2-60x=0

The zeros of 15x^2-60x=0 are x=4,x=0

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15 x^{2} - 60 x = 0

x = 4, x = 0

Solution steps

15 x^{2} - 60 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 60 ) \pm ( - 60 ) ^{2} - 4 \cdot 15 \cdot 0}{2 \cdot 15}

(- 60)^{2} - 4 \cdot 15 \cdot 0 = 60

x_{1, 2} = \frac{- ( - 60 ) \pm 60}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- ( - 60 ) + 60}{2 \cdot 15}, x_{2} = \frac{- ( - 60 ) - 60}{2 \cdot 15}

x = \frac{- ( - 60 ) + 60}{2 \cdot 15} : 4

x = \frac{- ( - 60 ) - 60}{2 \cdot 15} : 0

The solutions to the quadratic equation are:

x = 4, x = 0

x^{2} + 4 x - 30 = - 3 x - 3 x

9 x^{2} - 18 x = - 2

x^{2} + 6 = 27 x

x^{2} = (3 a)^{2} + (a 3)^{2}

4 x^{2} - 2 x

What are the solutions to the equation 15x^2-60x=0 ?
The solutions to the equation 15x^2-60x=0 are x=4,x=0
Find the zeros of 15x^2-60x=0
The zeros of 15x^2-60x=0 are x=4,x=0