What are the solutions to the equation 3y^2-6=-7y ?

The solutions to the equation 3y^2-6=-7y are y= 2/3 ,y=-3

Find the zeros of 3y^2-6=-7y

The zeros of 3y^2-6=-7y are y= 2/3 ,y=-3

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3 y^{2} - 6 = - 7 y

y = \frac{2}{3}, y = - 3

Decimal Notation

y = 0.66666 \dots, y = - 3

Solution steps

3 y^{2} - 6 = - 7 y

Move

7 y

to the left side

3 y^{2} - 6 + 7 y = 0

Write in the standard form

a x^{2} + b x + c = 0

3 y^{2} + 7 y - 6 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 3 ( - 6 )}{2 \cdot 3}

7^{2} - 4 \cdot 3 (- 6) = 11

y_{1, 2} = \frac{- 7 \pm 11}{2 \cdot 3}

Separate the solutions

y_{1} = \frac{- 7 + 11}{2 \cdot 3}, y_{2} = \frac{- 7 - 11}{2 \cdot 3}

y = \frac{- 7 + 11}{2 \cdot 3} : \frac{2}{3}

y = \frac{- 7 - 11}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

y = \frac{2}{3}, y = - 3

(11 a + 5) (6 a - 18) = 0

- (\frac{1}{4})^{4}

54 x^{3} y - 16 y^{4}

- 9 (x - 9) = 3 (x + 63)

\frac{3 - 1}{3 + 1}

What are the solutions to the equation 3y^2-6=-7y ?
The solutions to the equation 3y^2-6=-7y are y= 2/3 ,y=-3
Find the zeros of 3y^2-6=-7y
The zeros of 3y^2-6=-7y are y= 2/3 ,y=-3