What are the solutions to the equation 49x^2-35x+25=0 ?

The solutions to the equation 49x^2-35x+25=0 are x= 5/14+i(5sqrt(3))/(14),x= 5/14-i(5sqrt(3))/(14)

Find the zeros of 49x^2-35x+25=0

The zeros of 49x^2-35x+25=0 are x= 5/14+i(5sqrt(3))/(14),x= 5/14-i(5sqrt(3))/(14)

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49 x^{2} - 35 x + 25 = 0

x = \frac{5}{14} + i \frac{5 3}{14}, x = \frac{5}{14} - i \frac{5 3}{14}

Solution steps

49 x^{2} - 35 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 35 ) \pm ( - 35 ) ^{2} - 4 \cdot 49 \cdot 25}{2 \cdot 49}

Simplify

(- 35)^{2} - 4 \cdot 49 \cdot 25 : 353 i

x_{1, 2} = \frac{- ( - 35 ) \pm 35 3 i}{2 \cdot 49}

Separate the solutions

x_{1} = \frac{- ( - 35 ) + 35 3 i}{2 \cdot 49}, x_{2} = \frac{- ( - 35 ) - 35 3 i}{2 \cdot 49}

x = \frac{- ( - 35 ) + 35 3 i}{2 \cdot 49} : \frac{5}{14} + i \frac{5 3}{14}

x = \frac{- ( - 35 ) - 35 3 i}{2 \cdot 49} : \frac{5}{14} - i \frac{5 3}{14}

The solutions to the quadratic equation are:

x = \frac{5}{14} + i \frac{5 3}{14}, x = \frac{5}{14} - i \frac{5 3}{14}

x^{2} + 6 x + 3 = - 2

- 5 x^{2} - 7 x + 6 = 0

\frac{1}{12} y^{2} = - y - 3

3 x^{2} - 20 x = 0

y, y^{2} = x^{3} - 4 x^{2} - 25 x + 28

What are the solutions to the equation 49x^2-35x+25=0 ?
The solutions to the equation 49x^2-35x+25=0 are x= 5/14+i(5sqrt(3))/(14),x= 5/14-i(5sqrt(3))/(14)
Find the zeros of 49x^2-35x+25=0
The zeros of 49x^2-35x+25=0 are x= 5/14+i(5sqrt(3))/(14),x= 5/14-i(5sqrt(3))/(14)