What are the solutions to the equation 10x^2-2x-1=0 ?

The solutions to the equation 10x^2-2x-1=0 are x=(1+sqrt(11))/(10),x=(1-sqrt(11))/(10)

Find the zeros of 10x^2-2x-1=0

The zeros of 10x^2-2x-1=0 are x=(1+sqrt(11))/(10),x=(1-sqrt(11))/(10)

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10 x^{2} - 2 x - 1 = 0

x = \frac{1 + 11}{10}, x = \frac{1 - 11}{10}

Decimal Notation

x = 0.43166 \dots, x = - 0.23166 \dots

Solution steps

10 x^{2} - 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 10 ( - 1 )}{2 \cdot 10}

(- 2)^{2} - 4 \cdot 10 (- 1) = 211

x_{1, 2} = \frac{- ( - 2 ) \pm 2 11}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 11}{2 \cdot 10}, x_{2} = \frac{- ( - 2 ) - 2 11}{2 \cdot 10}

x = \frac{- ( - 2 ) + 2 11}{2 \cdot 10} : \frac{1 + 11}{10}

x = \frac{- ( - 2 ) - 2 11}{2 \cdot 10} : \frac{1 - 11}{10}

The solutions to the quadratic equation are:

x = \frac{1 + 11}{10}, x = \frac{1 - 11}{10}

2 x^{2} + x - 1

(7 x - 5) (3 x + 8) = 15 x + 12

x^{2} + 42 x = 0

13 x^{2} - 7 = 62

y, x^{2} + y^{2} = 81

What are the solutions to the equation 10x^2-2x-1=0 ?
The solutions to the equation 10x^2-2x-1=0 are x=(1+sqrt(11))/(10),x=(1-sqrt(11))/(10)
Find the zeros of 10x^2-2x-1=0
The zeros of 10x^2-2x-1=0 are x=(1+sqrt(11))/(10),x=(1-sqrt(11))/(10)