What are the solutions to the equation -5x^2-7x+5=0 ?

The solutions to the equation -5x^2-7x+5=0 are x=-(7+sqrt(149))/(10),x=(sqrt(149)-7)/(10)

Find the zeros of -5x^2-7x+5=0

The zeros of -5x^2-7x+5=0 are x=-(7+sqrt(149))/(10),x=(sqrt(149)-7)/(10)

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- 5 x^{2} - 7 x + 5 = 0

x = - \frac{7 + 149}{10}, x = \frac{149 - 7}{10}

Decimal Notation

x = - 1.92065 \dots, x = 0.52065 \dots

Solution steps

- 5 x^{2} - 7 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 ( - 5 ) \cdot 5}{2 ( - 5 )}

(- 7)^{2} - 4 (- 5) \cdot 5 = 149

x_{1, 2} = \frac{- ( - 7 ) \pm 149}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 149}{2 ( - 5 )}, x_{2} = \frac{- ( - 7 ) - 149}{2 ( - 5 )}

x = \frac{- ( - 7 ) + 149}{2 ( - 5 )} : - \frac{7 + 149}{10}

x = \frac{- ( - 7 ) - 149}{2 ( - 5 )} : \frac{149 - 7}{10}

The solutions to the quadratic equation are:

x = - \frac{7 + 149}{10}, x = \frac{149 - 7}{10}

x^{2} + 10 x + 25 = 24

\frac{5 \cdot x}{8} + \frac{x ^{2}}{51}

2 x^{2} - 25 x + 50 = 0

- 160 x^{2} + 450 x - 300 = 0

g (g + 10) = - 6

What are the solutions to the equation -5x^2-7x+5=0 ?
The solutions to the equation -5x^2-7x+5=0 are x=-(7+sqrt(149))/(10),x=(sqrt(149)-7)/(10)
Find the zeros of -5x^2-7x+5=0
The zeros of -5x^2-7x+5=0 are x=-(7+sqrt(149))/(10),x=(sqrt(149)-7)/(10)